Find palindrome number program in java using for loop
The word “palindrome” has a Greek origin, a word, number, or set of characters that reads the same forward and backwards. Some examples of a palindrome are MALAYALAM, 343, 2001002, etc. Palindrome in Java can be implemented using many ways. Here we will discuss some important ways:
- Using while loops
- Using for loops
- Using recursion
What is a Palindrome Number?
A Palindrome no. is the number that remains the same when its digits get reversed.
Ex: 15451, for example: If we take 131 and reverse it then after reversing the number remains the same.
Steps to Palindrome Number program
- Input the number from the user.
- Then Reverse it.
- Compare the number with the number entered by the user.
- If both the no.’s are the same then print the number as a palindrome
- Else print not a palindrome.
Example 1:
Finding Palindrome number Using while loop
import java.util.Scanner;
class expalindrome
{
public static void main(String args[])
{
int x,number, y=0,temp=0;
Scanner s=new Scanner(System.in);
System.out.println(“Enter any number: “);
number=s.nextInt();
x=number;
while(number>0)
{
x=number%10;
number=number/10;
temp=temp*10+x;
}
if(temp==y)
{
System.out.println(“Number is Palindrome”);
}
else
{
System.out.println(“not Palindrome”);
}
}
}
Output:
Enter any Number :
161
Number is Palindrome
Example 2:
Finding Palindrome number Using for loop
1) The number is called a palindrome if a number is equal to reverse of its number.
2) For loop repeats rem=num%10; s=(s*10)+rem these steps until num>0. If the condition is false, then it compares the s value with t, if both are equal then it prints the given number is a palindrome.
class Palindrome
{
public static void main(String arg[])
{
int num,t,s,rem;
Scanner sc=new Scanner(System.in);
System.out.println("Enter any number ");
num=sc.nextInt();
t=num;
for(s=0;num>0;num/=10)
{
rem=num%10;
s=(s*10)+rem;
}
if(s==t)
System.out.println(t+" is a palindrome number ");
else
System.out.println(t+" is not a palindrome number ");
}
}Output:
Enter any number
161
161 is a palindrome number
Enter any number
1231
1231 is not a palindrome number
Example 3:
Finding Palindrome number Using Using Recursion
1) Using the “Palin” object p, we will call the palindromeOrNot(a) method.
2) The method palindromeOrNot(int num) calls itself as palindromeOrNot(num) until num!=0, if num=0 then it returns sum and sum assigned to s and compares with t, if both are equal then it prints message as “palindrome number”.
class Palin
{
int sum=0,r;
int palindromeOrNot(int num)
{
if(num!=0)
{
r=num%10;
sum=(sum*10)+r;
num/=10;
palindromeOrNot(num);
}
return sum;
}
public static void main(String arg[])
{
int a,t,s;
Palin p=new Palin();
Scanner sc=new Scanner(System.in);
System.out.print("Enter a number :");
a=sc.nextInt();
t=a;
s=p.palindromeOrNot(a);
if(s==t)
System.out.println("Palindrome number ");
else
System.out.println("Not a Palindrome number ");
}
}Output:
Enter a number :123454321
Palindrome number
Find palindrome number program in java using for loop – Find palindrome number program in java using for loop – Find palindrome number program in java using for loop – Find palindrome number program in java using for loop
